SOLUTION: A bag contains a total of 8 batteries of which 3 is defective. Selecting 3 at random without replacement, determine the probability that none of the batteries you select are good.

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Question 476756: A bag contains a total of 8 batteries of which 3 is defective. Selecting 3 at random without replacement, determine the probability that none of the batteries you select are good.

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Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
A bag contains a total of 8 batteries of which 3 is defective.
Selecting 3 at random without replacement, determine the probability that none of the batteries you select are good.
First we find the numerator of the probability:

We have 3 good batteries and we must choose all 3.  
That's "3 choose 3". So the numerator is 3C3 or 1.

Next we find the denominator of the probability:

We have 8 batteries and we must choose any 3.  
That's "8 choose 3". So the denominator is 8C3 or 56.

P(choosing all 3 bad batteries) = 3C3%2F%288C3%29+=+1%2F56 
 
Edwin