SOLUTION: For questions 1 and 2 evaluate each infinte geometric series. 1. infinity (sign) sigma (sign) (-1/2)^n-1 n=1 2. infinity (sign) sigma (sign) 3(.4)^n-1 n=1
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-> SOLUTION: For questions 1 and 2 evaluate each infinte geometric series. 1. infinity (sign) sigma (sign) (-1/2)^n-1 n=1 2. infinity (sign) sigma (sign) 3(.4)^n-1 n=1
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Question 476754
:
For questions 1 and 2 evaluate each infinte geometric series.
1. infinity (sign)
sigma (sign) (-1/2)^n-1
n=1
2. infinity (sign)
sigma (sign) 3(.4)^n-1
n=1
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robertb(5830)
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