SOLUTION: A landscaper planted some trees and bushes in a new subdivision. The first order was for 12 bushes and 15 trees and cost $600. The second order was for 8 bushes and 20 trees and
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Question 476605: A landscaper planted some trees and bushes in a new subdivision. The first order was for 12 bushes and 15 trees and cost $600. The second order was for 8 bushes and 20 trees and cost $680. Find the price of each tree and bush. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A landscaper planted some trees and bushes in a new subdivision. The first order was for 12 bushes and 15 trees and cost $600. The second order was for 8 bushes and 20 trees and cost $680. Find the price of each tree and bush.
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12b + 15t = 600
8b + 20t = 680
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Modify:
4b + 5t = 200
4b +10t = 380
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Subtract and solve for "t":
5t = 180
t = 36 (# of trees)
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Solve for "b":
4b + 10t = 380
4b + 360 = 380
4b = 20
b = 5 (# of bushes)
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Cheers,
Stan H.
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