SOLUTION: solve for x {{{ log( 6,(2x+1) ) - log ( 6,(x-5) ) = 0 }}}

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Question 476521: solve for x
+log%28+6%2C%282x%2B1%29+%29+-+log+%28+6%2C%28x-5%29+%29+=+0+
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
log%286%2C%28%282x%2B1%29%2F%28x-5%29%29%29+=+0 by property of logarithms.
6%5E0+=+1+=%282x%2B1%29%2F%28x-5%29, the exponential equivalent.
==> x-5 = 2x+1 ==> x = -6.
If x = -6 is substituted into the original equation, we get
log%286%2C%28-11%29%29+-+log%286%2C%28-11%29%29+=+0, which is false ,
because both terms at the left-side are undefined.
Hence the equation has no solution.