Question 476519: lnx+ln(x-5)=ln6
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! lnx+ln(x-5)=ln6
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lnx+ln(x-5)-ln6=0
place under a single log
ln(x(x-5))/6=0
convert to exponential form:(base(e) raised to log of number(0)=number(x(x-5))/6
e^0=(x(x-5))/6=1
x^2-5x=6
x^2-5x-6=0
(x-6)(x+1)=0
x=6
or
x=-1 (reject, x>0)
Check:
lnx+ln(x-5)
ln(6)+ln(1)
ln(6)+0=ln(6)
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