SOLUTION: Karen moved into a new apartment she had four boxes for the kitchen and six boxes for the bedroom. The movers paid no attention to their contents and randomly placed four boxes in
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-> SOLUTION: Karen moved into a new apartment she had four boxes for the kitchen and six boxes for the bedroom. The movers paid no attention to their contents and randomly placed four boxes in
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Question 476505: Karen moved into a new apartment she had four boxes for the kitchen and six boxes for the bedroom. The movers paid no attention to their contents and randomly placed four boxes in the bedroom. Find the probability that three of the boxes were for the bedroom and one for the kitchen. Answer by Maths68(1474) (Show Source):
You can put this solution on YOUR website! Kitchen Boxes = 4
Bedroom Boxes=6
Total Boxes=10
Use
nCr=n! /(n-r)! r!
4 Boxes can be placed out of 10 Boxes = 10C4
= 10!/(10-4)!4!
= 10*9*8*7*6!/6! (4*3*2*1)
=5040/24
=210 ways
1 Kitchen box can be placed out of 4 = 4C1
= 4!/(4-1)! 1!
= 4!/3!1!
= 4*3!/3!
= 4 ways
3 Bedroom boxes can be placed out of 6 = 6C3
= 6!/(6-3)! 3!
= 6!/3!3!
= 6*5*4*3!/3! 3*2*1
= 6*5*4*/ 3*2*1
=120/6
=20 ways
P(1 kitchen box and 3 Bedroom boxes) = (4C1*6C3)/10C4
= (4*20)/210
=80/210
=8/21
=0.3809
