SOLUTION: Find the smallest of 3 consecutive integeres such that when 5 times the largest is subtracted from the square of the middle one the result exceeds three times the smallest by 7
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Question 476180: Find the smallest of 3 consecutive integeres such that when 5 times the largest is subtracted from the square of the middle one the result exceeds three times the smallest by 7 Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! (n+1)2-5(n+2)=3n+7
n2+2n+1-5n-10-3n-7=0
n2-6n-16=0
(n-8)(n+2)=0
n=8 or -2
n+1=9
n+2=10
The integers are 8,9, and 10..
