SOLUTION: I am very lost in this subject and I do need help and plenty of it as I get very flustered to say the least,If someone can help it would be greatly appreciated. With the questions

Algebra ->  Linear-equations -> SOLUTION: I am very lost in this subject and I do need help and plenty of it as I get very flustered to say the least,If someone can help it would be greatly appreciated. With the questions       Log On


   



Question 476154: I am very lost in this subject and I do need help and plenty of it as I get very flustered to say the least,If someone can help it would be greatly appreciated. With the questions I am about to ask I cam up with (0,5) The question is as follows:
1 Graph equation and identify Y Intercept Y=1/2 x +5
2. Graph by plotting points X=2
3 Graph the equation and plot points Y=1/5x

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Think of the equation as a long series of points
that make up a straight line. The straight line and the
equation are the same thing.
The convention for showing a point is:
(x,y)
You need both an x and a y to be a point, but they
must be points on this line.
You can determine the points this way:
(0,?)
(1,?)
(2,?)
(3,?)
(4,?)
(5,?)
etc.
Or, this way:
(?,0)
(?,1)
(?,2)
(?,3)
(?,4)
(?,5)
etc.
So, given the x or y, you can find the point that
falls on the line.
---------------
+y+=+%281%2F2%29%2Ax+%2B+5+
The y-intercept occurs where +x+=+0+
+y+=+%281%2F2%29%2A0+%2B+5+
+y+=+5+ is the y-intercept
The graph is:
+graph%28+400%2C+400%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F2%29%2Ax+%2B+5%29+
----------------------------
+x+=+2+
This just says: No matter what number I choose for y, I will
alway have +x+=+2+. The points on this line will look like:
(2,y), and y can be any number. This is plotted as a vertical line
--------------------------
+y+=+%281%2F5%29%2Ax+
+graph%28+400%2C+400%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F5%29%2Ax+%29+