SOLUTION: A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their area is 28 square feet, find the length of the sides of the poster

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Question 476014: A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their area is 28 square feet, find the length of the sides of the poster and the sign.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let a side of the square sign = +s+ ft
The area of the square sign = +s%5E2+ ft2
given:
A side of the square poster = +s+-+2+ ft
The area of the square poster = +%28s+-+2%29%5E2+ ft2
+s%5E2+-+%28s+-+2%29%5E2+=+28+ ft2
+s%5E2+-+s%5E2+%2B+4s+-+4+=+28+
+4s+-+4+=+28+
+4s+=+32+
+s+=+8+
A side of the square sign is 8 ft
A side of the square poster is 6 ft
check answer:
+s%5E2+-+%28s+-+2%29%5E2+=+28+
+8%5E2+-+%288+-+2%29%5E2+=+28+
+64+-+36+=+28+
+28+=+28+
OK