SOLUTION: Can you show me how to solve the following? It says write an equation of the line that goes through the point (-8,7) and is perpendicular to the line -4x+3y=11.

Algebra ->  Linear-equations -> SOLUTION: Can you show me how to solve the following? It says write an equation of the line that goes through the point (-8,7) and is perpendicular to the line -4x+3y=11.      Log On


   

Question 475995: Can you show me how to solve the following? It says write an equation of the line that goes through the point (-8,7) and is perpendicular to the line -4x+3y=11.
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
Find the slope of the given line 4x%2B3y=11
3y=-4x%2B11
y=%28-4%2F3%29x%2B11%2F3, the slope is m1=%28-4%2F3%29
Perpendicular lines are lines whose slopes are negative reciprocals of one another, m1%2Am2=-1
then the slope of the line that we have to find m2=-1%2F%28m1%29
m2=-1%2F%28-4%2F3%29=3%2F4
The point-slope form of a line uses a point (x1,y1) and a slope (m), to write the equation of a line. This form is given by the equation:
y+-+y1=+m%28x+-+x1%29
Point (-8,7) substitue into formula x1=-8, y1=7; m=3%2F4+
y-7=%283%2F4%29%28x-%28-8%29%29 multiply by 4
4y-28=3x%2B24
3x-4y=-52