SOLUTION: Supose an amoeba divids into two amoebas one every hour.How long would it take for a single amoeba to become acolony of 4096 amoebas? the key is 12 hours Page 673

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Supose an amoeba divids into two amoebas one every hour.How long would it take for a single amoeba to become acolony of 4096 amoebas? the key is 12 hours Page 673      Log On


   



Question 475959: Supose an amoeba divids into two amoebas one every hour.How long would it take for a single amoeba to become acolony of 4096 amoebas?
the key is 12 hours
Page 673

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The size of the colony doubles every hour
The progression is:
1
2
4
8
16
32
64
128
256
512
1024
2048
4096
The 1st amoeba is already there, so you
don't count it. Each step is 1 hour, so
there are 12 hours
The formula is:
Colony size = +2%5En+
where +n+ is the number of hours elapsed