SOLUTION: From 6 chemists and 5 biologists, a committee of 7 is to be chosen so as to include 4 chemists. In how many ways can this be done?
Here is how I did it:
11C4 times 7C3 = 82
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-> SOLUTION: From 6 chemists and 5 biologists, a committee of 7 is to be chosen so as to include 4 chemists. In how many ways can this be done?
Here is how I did it:
11C4 times 7C3 = 82
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Question 475903: From 6 chemists and 5 biologists, a committee of 7 is to be chosen so as to include 4 chemists. In how many ways can this be done?
Here is how I did it:
11C4 times 7C3 = 8250 but it is the wrong answer. Where did I went wrong? Please help me figure this one out. Thank you very much.
I. Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! 1 committee=4 chemists, 3 biologists=
6C4 X 5C3=(6x5x4x3x2!/4x3x2x2!) X (5x4x3x2!/3x2x2!)=
(5x3) X (5x2)=15 X 10=150..
