Question 475902: .Consider college officials in admissions registration, counseling, financial aid campus ministry, food services, and so on. How much money do these people make each year? Suppose you read in your local newspaper that 45 officials in student services earn an average of $50,340 each year. Assume that the standard deviation is $10,780 for salaries of college officials and student services. Find a 90% confidence interval for the population mean salaries of such personnel. Round your answer to the nearest dollar and don;t forget to use the $ sign.
2.What is the margin of error for problem 1? Round your answer to the nearest dollar and don;t forget to use the $ sign.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Consider college officials in admissions registration, counseling, financial aid campus ministry, food services, and so on. How much money do these people make each year?
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Suppose you read in your local newspaper that 45 officials in student services earn an average of $50,340 each year.
x-bar = 50,340
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Assume that the standard deviation is $10,780 for salaries of college officials and student services.
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Find a 90% confidence interval for the population mean salaries of such personnel.
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x-bar = 50340
ME = 1.645*10780/[sqrt(45)] = 2643.50
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90%CI: 50340-2643.50 < u < 50340+2643.50
90%CI: 47696.50 < u < 52983.50
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Round your answer to the nearest dollar and don;t forget to use the $ sign.
2.What is the margin of error for problem 1? Round your answer to the nearest dollar and don;t forget to use the $ sign.
ME = 1.645*10780/[sqrt(45)] = 2643.50
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Cheers,
Stan H.
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