SOLUTION: What are the zeros if P(x) and their multiplicities: P(x)=(x+5)^3(x-6)(-x+6)

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Question 475727: What are the zeros if P(x) and their multiplicities: P(x)=(x+5)^3(x-6)(-x+6)

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

P%28x%29=%28x%2B5%29%5E3%28x-6%29%28-x%2B6%29....set P%28x%29=0

%28x%2B5%29%5E3%28x-6%29%28-x%2B6%29=0...the product is equal to zero if any of multiplicands is equal to zero
%28x%2B5%29%5E3=0...->....%28x%2B5%29=0...->....x=-5
%28x-6%29=0...->....%28x-6%29=0...->....x=6
%28-x%2B6%29=0...->....6=x...or....x=6
so, zeros are:x=-5 and x=6