Question 475616: You have measured the percentage of days your company met production targets across two sites. At one site, you measure 80 days and found that the site missed the production goals 11 times. At site two, you measured 92 days and found that the site missed the production goals 10 times. At the 90% confidence level, can you say that site two missed the production goal fewer times than site one? State your hypothesis:
Found 2 solutions by stanbon, edjones:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! You have measured the percentage of days your company met production targets across two sites.
At one site, you measure 80 days and found that the site missed the production goals 11 times.
p1-hat = 11/80
-----------------------
At site two, you measured 92 days and found that the site missed the production goals 10 times.
p2-hat = 10/92
-----------------------
At the 90% confidence level, can you say that site two missed the production goal fewer times than site one? State your hypothesis:
Ho: p1-p2 <= 0
Ha: p1-p2 > 0 (claim)
-----------------
I ran a 2-PropZtest on my TI-84 calculator and got the following:
test statistic: z = 0.5755
p-value = 0.2825
---
Conclusion: Since the p-value is greater than 5%, fail to reject
Ho at the 5% level of significance.
--------------------
Cheers,
Stan H.
================
Answer by edjones(8007)  (Show Source):
You can put this solution on YOUR website! H[o]: site two missed the production goal fewer times than site one.
Site #1: p=11/80=.1375, q=1-.1375=.8625, n=80
Site #2: p=10/92=.1087, q=1-.1087=.8913, n=92
 =.0385+.0325=.071
z=(.1375-.1087)/.071=.4056
Using a single tailed test z=.4056 has an area of .3245 under the normal curve and the null hypothesis is not confirmed.
.
Ed
|
|
|
