SOLUTION: Find three consecutive even integers, such that 7 times the middle integer is 10 more than the sum of first and third.
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Question 475587
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Find three consecutive even integers, such that 7 times the middle integer is 10 more than the sum of first and third.
Answer by
mananth(16946)
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let x,x+2,x+4 be the integers
7(x+2)= x+x+4+10
7x+14=2x+14
5x=0
x=0
0,2,4