Question 47553This question is from textbook Beginning Algebra
: From TEXTBOOK
Need help solving this word problem and I need to show the equation that was used to get the solution.
A bus leaves a station at 1 pm., travelling westat an average rate of 44mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48mi/h. At what time will two buses be 274 mi apart?
Thank You!
This question is from textbook Beginning Algebra
Answer by josmiceli(19441)   (Show Source):
You can put this solution on YOUR website! You need two stopwatches and each must have a cellphone. The stop watches
will show what time each started and the elapsed time untill they are
274 miles apart. With ther cells, they can tell eachother how far they've
gone from the start.
t = 1st bus time
t - 1 = 2nd bus time
44t + 48(t - 1) = 274
44t + 48t -48 = 274
92t = 322
t = 3.5 hours
This is the elapsed time for the 1st bus when they are 274 miles apart.
1 PM + 3.5 hrs = 4:30 PM answer
The time on the 2nd stopwatch will show 2.5 hours, and the 2nd bus left
at 2 PM. So, it got to it's stopping point at
2 PM + 2.5 hrs = 4:30 PM just as it should (they stop at the same time)
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