You can put this solution on YOUR website! Find two consecutive odd integers whose product exceeds three times their sum by 15.
:
x(x+2) = 3(x + (x+2)) + 15
x^2 + 2x = 3(2x+2) + 15
x^2 + 2x = 6x + 6 + 15
x^2 + 2x - 6x - 21 = 0
x^2 - 4x - 21 = 0
Factors to
(x+3)(x-7) = 0
Two solutions
x = -3
x = 7
:
You can check both solutions in the original equation