SOLUTION: find the area of a box with dimensions sqrt 3 + sqrt 5 (length) and sqrt 3 + sqrt 5 (height)

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Question 47530: find the area of a box with dimensions sqrt 3 + sqrt 5 (length) and sqrt 3 + sqrt 5 (height)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find the area of a box with dimensions sqrt 3 + sqrt 5 (length) and sqrt 3 + sqrt 5 (height)
Use FOIL as follows:
F: sqrt3 * sqrt3 = 3
O: sqrt3 * sqrt5 = sqrt15
I: sqrt5 * sqrt3 = sqrt15
L: sqrt5 * sqrt% = 5
Combine to get:
8 + 2sqrt(15)
Cheers,
Stan H.