SOLUTION: the average score of all golfers for a particular course has a mean of 80 and a standard deviation of 5. suppose 100 golfers played the course today. find the probability that the
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Question 475219: the average score of all golfers for a particular course has a mean of 80 and a standard deviation of 5. suppose 100 golfers played the course today. find the probability that the average score of the 100 golfers exceeds 81 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! the average score of all golfers for a particular course has a mean of 80 and a standard deviation of 5. suppose 100 golfers played the course today. find the probability that the average score of the 100 golfers exceeds 81
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t(81) = (81-80)/[5/sqrt(100)] = 1/(1/2)= 2
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P(x > 81) = P(t > 2 when df = 99) = 0.0241
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Cheers,
Stan H.
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