SOLUTION: How would I graph the equation and identify the y-intercept with problem y=-1/2x-4

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Question 475185: How would I graph the equation and identify the y-intercept with problem y=-1/2x-4
Found 2 solutions by rfer, MathLover1:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
y=mx+b
b= y int
b=-4
(0,-4)
----------
slope m=-1/2
so from (0,-4)
go two right and one down and so on.
(2,-5)
(4,-6)

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

y=-%281%2F2%29x-4.....you have here a linear equation and the graph will be a line..to graph a line you need two points that lie on a line because a line is defined by two points
your equation is also written in slope-intercept form y=mx%2B-b where m is a slope and b is y-intercept
so, here y=-%281%2F2%29x-4 y-intercept is b=-4 and that is one point; (0,-4)
now you can find second point: if you take y=0 you will find x-intercept
0=-%281%2F2%29x-4
%281%2F2%29x=-4
x=-4%2F%281%2F2%29
x=-8.....so, the second point is -8%2C0
now you can plot a line:
+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C-%281%2F2%29x-4%29+