SOLUTION: Please help me to solve this equation: solve 3x^2+13x+14=0

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Question 475104: Please help me to solve this equation:
solve
3x^2+13x+14=0
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
3x^2+13x+14=0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 3x%5E2%2B13x%2B14+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%2813%29%5E2-4%2A3%2A14=1.

Discriminant d=1 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-13%2B-sqrt%28+1+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%2813%29%2Bsqrt%28+1+%29%29%2F2%5C3+=+-2
x%5B2%5D+=+%28-%2813%29-sqrt%28+1+%29%29%2F2%5C3+=+-2.33333333333333

Quadratic expression 3x%5E2%2B13x%2B14 can be factored:
3x%5E2%2B13x%2B14+=+%28x--2%29%2A%28x--2.33333333333333%29
Again, the answer is: -2, -2.33333333333333. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B13%2Ax%2B14+%29