Question 47507: Find the odds against obtaining two (2) heads in a single toss of two coins.
Is it 1/2 Found 2 solutions by stanbon, venugopalramana:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the odds against obtaining two (2) heads in a single toss of two coins.
"Odds against event A" = [P(not A)]/[P(A)]
P(2 heads) = 1/4
P( not 2 heads) = 3/4
Therefore Odds against 2 heads = (3/4)/(1/4) = 3:1
Cheers,
Stan H.
You can put this solution on YOUR website! Find the odds against obtaining two (2) heads in a single toss of two coins.
Is it 1/2...NO...
THERE ARE 2 POSSIBILITIES IN EACH TOSS ...PROBABILITY OF HEAD IN ONE TOSS=1/2
SAME IS CASE IN SECOND TOSS =1/2
HENCE PROBABILITY OF GETTING 2 HEADS IN 2 TOSSES =(1/2)*(1/2)=1/4
PROBABILITY AGAINST 2 HEADS =1-1/4=3/4
ODDS AGAINST 2 HEADS ARE 3/4:1/4=3:1
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