SOLUTION: Use properties of logarithms to solve the equation log(base3)y – log(base3)7 = log(base3)2

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Question 475029: Use properties of logarithms to solve the equation log(base3)y – log(base3)7 = log(base3)2
Answer by nerdybill(7384) About Me  (Show Source):
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Use properties of logarithms to solve the equation log(base3)y – log(base3)7 = log(base3)2
log%283%2Cy%29+-+log%283%2C7%29+=+log%283%2C2%29
log%283%2Cy%2F7%29+=+log%283%2C2%29
y%2F7+=+2
y+=+14