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B |2x-1| < -3 has an empty solution set because absolute
values are never negative, and for the absolute value |2x-1|
to be less than -3 it would have to be negative, which is
impossible.
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[Some people might think D |2x-1| ≤ 0 would be the answer
but it isn't because even though |2x-1| can't be less than 0 it
can be EQUAL to 0 and ≤ says "less than OR EQUAL 0", so it
CAN equal 0. Thus D is not the answer.]
Edwin