SOLUTION: Two cyclists leave towns 70mi apart at the same time and travel toward each other. One cyclist travels 3mi/h faster than the other. If they meet in 2 hours, what is the rate of eac
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Question 474895: Two cyclists leave towns 70mi apart at the same time and travel toward each other. One cyclist travels 3mi/h faster than the other. If they meet in 2 hours, what is the rate of each cyclist? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Two cyclists leave towns 70mi apart at the same time and travel toward each other. One cyclist travels 3mi/h faster than the other. If they meet in 2 hours, what is the rate of each cyclist?
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let x=rate of speed of slower cyclist
x+3= rate of speed of faster cyclist
..
distance = speed*travel time
2x+2(x+3)=70
2x+2x+6=70
4x=64
x=16
x+3=19
ans:
rate of speed of slower cyclist=16 mph
rate of speed of faster cyclist=19 mph
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