SOLUTION: After j candies were given to k kids, each kid has the same number of candies, with four candies remaining. In terms of j and k, how many candies did each kid get? A) (j/k) + 4

Algebra ->  Divisibility and Prime Numbers -> SOLUTION: After j candies were given to k kids, each kid has the same number of candies, with four candies remaining. In terms of j and k, how many candies did each kid get? A) (j/k) + 4       Log On


   



Question 474837: After j candies were given to k kids, each kid has the same number of candies, with four candies remaining. In terms of j and k, how many candies did each kid get?
A) (j/k) + 4
B) (j/k) - 4
C) (j + 4)/k
D) (j - 4)/k
E) (jk)/k + 4
Please explain how I could approach and solve this problem, thanks!

Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
There were j candies, but j-4 were actually given (since there was a remainder of 4). This was distributed over k kids, so each kid got (j-4)/k candies.