SOLUTION: Find all solutions of the system y+x^2=4x y+4x=16

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Question 474788: Find all solutions of the system
y+x^2=4x
y+4x=16
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
y+x^2=4x
y+4x=16
y=4x-x^2
substitute y in second equation
y+4x=16
4x-x^2+4x=16
x^2-8x+16=0
(x-4)^2=0
x=4