SOLUTION: Three less than twice the third of three consecutive integers equals the sum of the three integers. Find the integers.
I have this so far:
2(abc/3)-3 = a+b+c
a=integer #1,
Algebra ->
Problems-with-consecutive-odd-even-integers
-> SOLUTION: Three less than twice the third of three consecutive integers equals the sum of the three integers. Find the integers.
I have this so far:
2(abc/3)-3 = a+b+c
a=integer #1,
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Question 474599: Three less than twice the third of three consecutive integers equals the sum of the three integers. Find the integers.
I have this so far:
2(abc/3)-3 = a+b+c
a=integer #1, b=integer # 2, and c=integer # 3 Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! Instead of letting the integers being a,b,c (this makes for a three-variable equation which might not be solvable) we take advantage that the integers are consecutive, so we let the integers be a, a+1, and a+2. Then,
