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| Question 47444:  Please help
 In a chemistry class, 6 liters of a 4% silver iodide solution must be mixed with a 10% solution to get a 6%
 solution. How many liters of the 10% solution are needed?
 
 Answer by longjonsilver(2297)
      (Show Source): 
You can put this solution on YOUR website! Mixture questions are all about BEFORE = AFTER since the "BEFORE's" mix to become the "AFTER", so they have to be "equal". 
 Right, a definition so we know what x is: Let x be the amount of the 10% solution.
 Once mixed, how much will we have? we will have (x+6) litres, surely? :-)
 
 BEFORE:
 0.04*6 and 0.10x
 
 AFTER:
 0.06*(x+6)
 
 So, 0.04*6 + 0.10x = 0.06*(x+6)
 0.24 + 0.10x = 0.06x + 0.36
 0.24 + 0.04x = 0.36
 0.04x = 0.12
 x = 0.12/0.04
 x = 3litres
 
 jon
 
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