SOLUTION: A chemist needs to strengthen a 15% acid solution so thta it contains 32% acid. How much pure acid should be added to 200 milliliters of a 15% solution in order to reach her goal

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A chemist needs to strengthen a 15% acid solution so thta it contains 32% acid. How much pure acid should be added to 200 milliliters of a 15% solution in order to reach her goal      Log On


   



Question 47430: A chemist needs to strengthen a 15% acid solution so thta it contains 32% acid. How much pure acid should be added to 200 milliliters of a 15% solution in order to reach her goal?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
200*.15+X=(200+X).32 OR 30+X=64+.32X OR X-.32X=64-30 OR .68X=34 OR X=34/.68 OR
X=50ML OF PURE ACID NEEDS TO BE ADDED.