SOLUTION: A lab assistant is asked to mix a 30% alcohol solution with 21 liters of an 80% alcohol solution to make a 60% alcohol solution. How many liters of the 30% alcohol solution should
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Question 474192: A lab assistant is asked to mix a 30% alcohol solution with 21 liters of an 80% alcohol solution to make a 60% alcohol solution. How many liters of the 30% alcohol solution should be used? Answer by ewatrrr(24785) (Show Source):
Hi,
Let x represent the amount of the 30% solution
MIXING
.30x + .80*21L = .60(x+21L)
.20*21L = .30x
x = .20*23L/.3 = 14L, the amount of the 30% solution