SOLUTION: Find the the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=-2x^2+2x+7 The x coordinate of the vertex is ___. (Type a sim

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Find the the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=-2x^2+2x+7 The x coordinate of the vertex is ___. (Type a sim      Log On


   

Question 473950: Find the the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=-2x^2+2x+7
The x coordinate of the vertex is ___. (Type a simplified fraction.)
The y coordinate of the vertex is ___. (Type a simplified fraction.)
The equation of the line of symmetry is x=____. (Type a simplified fraction.)
The maximum/minimum of f(x) is ___ .(Type a simplified fraction.)
Then please draw a picture of the correct graph.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Note: the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

 f(x)= -2x^2+2x+7 = -2(x-.5)^2 +  15/2   |completing Square

V(.5,7.5), a = -2, -2<0, Parabola open downward.  Vertex is a max point

x = .5 is the line of symmetry

Maximimum value for the functions is 7.5