SOLUTION: Find four consecutive integers such that the product of the two larger integers is 22 less than twice the product of the two smaller integers.

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Question 473946: Find four consecutive integers such that the product of the two larger integers is 22 less than twice the product of the two smaller integers.
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
2(n)(n+1)-22=(n+2)(n+3)
2n2+2n-22=n2+5n+6
n2-3n-28=0
(n-7)(n+4)=0
n=-4 or 7
Throwing out the negative answer, we get the consecutive integers to be 7,8,9,and 10..