SOLUTION: How do i solve this log5^7+1/2log5^4=log5^x

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Question 473939: How do i solve this log5^7+1/2log5^4=log5^x
Answer by ccs2011(207) About Me  (Show Source):
You can put this solution on YOUR website!
Use the following log rules:
log(a) + log(b) = log(ab)
log(a) - log(b) = log(a/b)
log(a^n) = n*log(a)
--> log+5%5E7+=+7%2Alog+5
--> %281%2F2%29log+5%5E4+=+%284%29%281%2F2%29log+5+=+2%2Alog+5
--> log+5%5Ex+=+x%2Alog+5
Now the equation looks like this:
7%2Alog+5+%2B+2%2Alog+5+=+x%2Alog+5
Add like terms
9%2Alog+5+=+x%2Alog+5
Divide by log(5) on both sides
9+=+x
Solution is x = 9