Question 473898: the length of a rectangle is 3 more than twice its width. if the perimeter is 54 inches, what is the width of the rectangle?
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! "the length of a rectangle is 3 more than twice its width. if the perimeter is 54 inches, what is the width of the rectangle?"
x = width
2x + 3 = length {length is 3 more than twice width}
Perimeter of a rectangle is 2(width) + 2(length)
2x + 2(2x + 3) = 54 {perimeter = 2(width) + 2(length)}
2x + 4x + 6 = 54 {used distributive property}
6x + 6 = 54 {combined like terms}
6x = 48 {subtracted 6 from both sides}
x = 8 {divided both sides by 6}
2x + 3 = 19 {substituted 8, in for x, into 2x + 3}
width = 8 and length = 19
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