SOLUTION: x-y=2 (1) 3x-4z=15 (2) 3y+z=9 (3) Is there a solution and if there is what are the solutions?

Algebra ->  College  -> Linear Algebra -> SOLUTION: x-y=2 (1) 3x-4z=15 (2) 3y+z=9 (3) Is there a solution and if there is what are the solutions?      Log On


   

Question 473688: x-y=2 (1)
3x-4z=15 (2)
3y+z=9 (3)
Is there a solution and if there is what are the solutions?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
x-y=2
3x-4z=15
3y+z=9
---------------
x - y + 0 = 2
3x + 0 -4z = 15
0 +3y + z = 9
-------------------------
Use any method you know to get:
x = 5
y = 3
z = 0
===============
Cheers,
Stan H.
==============