SOLUTION: if p+q=4 and p^2+q^2=7,then the value of p/q is

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Question 473683: if p+q=4 and p^2+q^2=7,then the value of p/q is
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
if p+q=4 and p^2+q^2=7,then the value of p/q is
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p = 4-q
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Substitute for "p" and solve for "q":
(4-q)^2 + q^2 = 7
16-8q+2q^2 = 7
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2q^2-8q - 23 = 0
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q = [8 +- sqrt(64 - 4*2*-23)]/4
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q = [8 +- sqrt(248]]4
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q = [8 +- 2sqrt(62)]/4
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q = [2 + (1/2)sqrt(62)] or q = [2 - (1/2)sqrt(62)]
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p/q = (4-q)/[2 + (1/2)sqrt(62)] or p/q = (4-q)/[2 - (1/2)sqrt(62)]
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Cheers,
Stan H.