SOLUTION: Solve the absolute value inequality. Write the answer in interval notation. The problem is: |5-2x over 6|< or equal to 3 - can you show me how to solve this. I thought you have to

Algebra ->  Inequalities -> SOLUTION: Solve the absolute value inequality. Write the answer in interval notation. The problem is: |5-2x over 6|< or equal to 3 - can you show me how to solve this. I thought you have to      Log On


   



Question 473513: Solve the absolute value inequality. Write the answer in interval notation. The problem is: |5-2x over 6|< or equal to 3 - can you show me how to solve this. I thought you have to multiply the 6 by all the numbers, but I'm not getting the correct answer. Thanks.
Found 2 solutions by stanbon, ccs2011:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
|5-2x over 6|< or equal to 3
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|(5-2x)/6| <= 3
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Solve: -3 <= (5-2x)/6 <=3
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Multiply thru by 6 to get:
-18 <= 5-2x <= 18
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Subtract 5 along the line:
-23 <= -2x <= 13
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Divide thru by -2
-13/2 <= x <= 23/2
============================
Cheers,
Stan H.

Answer by ccs2011(207) About Me  (Show Source):
You can put this solution on YOUR website!
abs%28%285-2x%29%2F6%29+%3C=+3
Since we are dealing with an absolute value you have to deal with the negative case as well.
%285-2x%29%2F6 can be any number from -3 to 3 because the absolute value turn all the negative values positive
Rewrite inequality without absolute value signs
-3+%3C=+%285-2x%29%2F6+%3C=+3
Now you multiply equation by 6
-18+%3C=+5-2x+%3C=+18
Subtract 5 from both sides
-23+%3C=+-2x+%3C=+13
Divide by -2 on both sides
**Important: when dividing by a negative flip the inequality**
EX: -x < 3 = x > -3 , If you change the sign then flip the inequality.
After dividing and flipping the inequality
23%2F2+%3E=+x+%3E=+-13%2F2
Interval notation, use brackets for ">=" parenthesis for ">"
x is any real number in [-6.5, 11.5]