SOLUTION: solve by the elimination method: 2r-3s= -14 3r+2s=18

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Question 473211: solve by the elimination method:
2r-3s= -14
3r+2s=18
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
2r-3s= -14
3r+2s=18


2(2r-3s)= 2(-14)
3(3r+2s)=3(18)


4r-6s=-28
9r+6s=54


13r=26
r=26/13
r=2

2r-3s=-14
2(2)-3s=-14
4-3s=-14
-3s=-14-4
-3s=-18
s=-18/(-3)
s=6

Answers: r=2 and s=6

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
solve by the elimination method:
2r-3s= -14
3r+2s = 18
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Multiply the 1st eqn by 2 and the 2nd eqn by 3, then add them.
4r-6s = -28
9r+6s = 54
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