SOLUTION: I need help solving this equation. One side is 'x' the other 'x+12' and the hypotenuse is '60'. How can I solve this?

Algebra ->  Pythagorean-theorem -> SOLUTION: I need help solving this equation. One side is 'x' the other 'x+12' and the hypotenuse is '60'. How can I solve this?      Log On


   

Question 473172: I need help solving this equation. One side is 'x' the other 'x+12' and the hypotenuse is '60'. How can I solve this?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

One side is 'x' the other 'x+12' and the hypotenuse is '60'

Applying the Pythagorean Theorem

 x^2 + (x+12)^2 = 3600

  2x^2 + 24x + 144 = 3600

   2x^2 + 24x -3456 = 0

   x^2 + 12x - 1728 = 0

factoring  (or using the Quadratic Formula)

  (x+48)(x-36) = 0

    (x+48)=0  x = -48  |tossing out negative solution for length

   (x-36) = 0 

     x = 36 and the other side = 48



CHECKING our Answer***

 1296 + 2304 = 3600