SOLUTION: please help me solve the problem,
What is the center of the hyperbola?
(x-2)^2/9-(y-5)^2/4=1
is it (3,2) 0r (9,4) or (2,5)
i tryed grafting this but it doesn't give any cente
Algebra ->
Quadratic-relations-and-conic-sections
-> SOLUTION: please help me solve the problem,
What is the center of the hyperbola?
(x-2)^2/9-(y-5)^2/4=1
is it (3,2) 0r (9,4) or (2,5)
i tryed grafting this but it doesn't give any cente
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Question 47317: please help me solve the problem,
What is the center of the hyperbola?
(x-2)^2/9-(y-5)^2/4=1
is it (3,2) 0r (9,4) or (2,5)
i tryed grafting this but it doesn't give any center when i graft it where did i go wrong?
You can put this solution on YOUR website! (x-2)^2/9-(y-5)^2/4=1
The equation follows the form:
(x-h)^2/a^2 - (y-k)^2/b^2 = 1
which has its center at (h,k)
Therefore the center for your hyperbola
is (2,5)
Cheers,
Stan H.
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