SOLUTION: Three consecutive odd integers are such that the square of the third integer is 15 more than the sum of the squares of the first two. Find the integers.

Algebra ->  Human-and-algebraic-language -> SOLUTION: Three consecutive odd integers are such that the square of the third integer is 15 more than the sum of the squares of the first two. Find the integers.      Log On


   



Question 473111: Three consecutive odd integers are such that the square of the third integer is 15 more than the sum of the squares of the first two. Find the integers.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Three consecutive odd integers are such that the square of the third integer is 15 more than the sum of the squares of the first two. Find the integers.
-------------------
The numbers are x, x+2 and x+4
x%5E2+%2B+%28x%2B2%29%5E2+=+%28x%2B4%29%5E2+-+15
2x%5E2+%2B+4x+%2B+4+=+x%5E2+%2B+8x+%2B+1
x%5E2+-+4x+%2B+3+=+0
(x - 1)*(x - 3) = 0
x = 1 --> 1, 3 & 5
x = 3 --> 3, 5 & 7
-------------------