SOLUTION: (x-6)^2+(y+5)^2=21

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Question 473097: (x-6)^2+(y+5)^2=21
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
%28x-6%29%5E2%2B%28y%2B5%29%5E2=21
it's a circle
for a circle with center (j, k) and radius (r):

+%28x-j%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
so, you have center (j, k)=(6,-5) and radius r=sqrt%2821%29=4.58
Solved by pluggable solver: PLOT any circle and describe it

Diameter: d+=+2r+=+2%2A4.58+=+9.16.
Area: area+=+pi%5Cr%5E2+=+pi%2A4.58%5E2+=+65.8993049861992
Perimeter: perimeter+=+2%5Cpi%5Cr+=+2%5Cpi%2A4.58+=+28.7769890769429