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Question 472728: Find two consecutive even integers such that 4 times the smaller number is two more than 3 times the larger number.
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! let x be the smaller number.
let x + 2 be the larger number.
4 times the smaller number is 2 more than 3 times the larger number.
in equation form, this becomes:
4x = 3 * (x+2) + 2
simplify this to get:
4x = 3x + 6 + 2 which becomes:
4x = 3x + 8
subtract 3x from both sides of this equation to get:
x = 8
this means that x+2 = 10
the smaller number is 8 and the larger number is 10.
4 times the smaller number is equal to 32.
3 times the larger number + 2 is equal to 32.
requirements of the problem check out ok, so the solution is good.
the smaller number is 8.
the larger number is 10.
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