SOLUTION: The half-life of Palladium-100 is 4 days. After 16 days a sample of Palaladium-100 has been reduce to a mass of 3 mg. What was the initial mass of the sample? What is the ma

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: The half-life of Palladium-100 is 4 days. After 16 days a sample of Palaladium-100 has been reduce to a mass of 3 mg. What was the initial mass of the sample? What is the ma      Log On


   



Question 472662: The half-life of Palladium-100 is 4 days. After 16 days a sample of Palaladium-100 has been reduce to a mass of 3 mg.
What was the initial mass of the sample?
What is the mass 7 weeks after the start?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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The half-life of Palladium-100 is 4 days.
After 16 days a sample of Palaladium-100 has been reduce to a mass of 3 mg.
What was the initial mass of the sample?
What is the mass 7 weeks after the start?
:
The half-life formula: A = Ao*2^(-t/h)
Where
A = resulting amt after t time
Ao = initial amt
t = time of decay
h = half-life of substance
:
Find the initial amt
Ao*2^(-16/4) = 3
Ao*2^-4 = 3
.0625*Ao = 3
Ao = 3%2F.0625
Ao = 48 mg is the initial amt
:
Find the amt after 7*7 = 49 days
A = 48*2^(-49/4)
Enter above into a calc
A = .00985 mg after 7 weeks