SOLUTION: I am trying to solve the following problem. Find the missing dimension of a rectangle. A=2x^2+x-6 w=x+2 A=lw 2x^2+x-6=l(x+2) Solve for l (2x^2+x-6)/(x+2)=l This

Algebra ->  Rational-functions -> SOLUTION: I am trying to solve the following problem. Find the missing dimension of a rectangle. A=2x^2+x-6 w=x+2 A=lw 2x^2+x-6=l(x+2) Solve for l (2x^2+x-6)/(x+2)=l This      Log On


   

Question 472661: I am trying to solve the following problem. Find the missing dimension of a rectangle.
A=2x^2+x-6
w=x+2
A=lw
2x^2+x-6=l(x+2) Solve for l
(2x^2+x-6)/(x+2)=l
This is as far as I have gotten. Will you please show me step by step how to get to this answer:
l=2x-3
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
I am trying to solve the following problem. Find the missing dimension of a rectangle.
A=2x^2+x-6
w=x+2
A=lw
2x^2+x-6=l(x+2) Solve for l
(2x^2+x-6)/(x+2)=l
This is as far as I have gotten. Will you please show me step by step how to get to this answer:
l=2x-3
**
The other missing dimension is the width which is given as w=x+2
A=lw=(2x-3)(x+2)=2x^2+x-6