SOLUTION: 1+(4/3){{{ log(x-3, 4 ) }}} =11/3 Solve for x. Please I need help.

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Question 472548: 1+(4/3)+log%28x-3%2C+4+%29+ =11/3
Solve for x. Please I need help.

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
1+(4/3)log(x-3) (4) =11/3
Solve for x. Please I need help.
**
(4/3)log(x-3) (4) =11/3-1=11/3-3/3=8/3
log(x-3) (4)=24/12=2
convert to exponential form: (base(x-3) raised to log of number (2)=number=4)
(x-3)^2=4
x-3=±√4=±2
x=3+2=5
or
x=3-2=1 (reject, (x-3)>1)
ans:
x=5