SOLUTION: In an isosceles triangle, the length of each leg exceeds twice the base by 2 cm. The perimeter is 24. How long is each leg?
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Question 472447: In an isosceles triangle, the length of each leg exceeds twice the base by 2 cm. The perimeter is 24. How long is each leg? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! In an isosceles triangle, the length of each leg exceeds twice the base by 2 cm. The perimeter is 24. How long is each leg?
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Draw a diagram of the problem, it'll help you see the solution.
Let b = length of base
then
2b+2 = length of leg
.
2(2b+2) + b = 24
4b+4 + b = 24
5b = 20
b = 4 cm (base)
.
length of the two legs:
2b+2 = 2(4)+2 = 10 cm
