SOLUTION: Help please!
Three people are selected at random from five females and nine males. Find the probability of the following. (to three decimal places.)
a) At least one is a male.
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-> SOLUTION: Help please!
Three people are selected at random from five females and nine males. Find the probability of the following. (to three decimal places.)
a) At least one is a male.
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Question 472389: Help please!
Three people are selected at random from five females and nine males. Find the probability of the following. (to three decimal places.)
a) At least one is a male.
b) At most two are male. Answer by sudhanshu_kmr(1152) (Show Source):
You can put this solution on YOUR website! 5 females and 9 males
Number of ways to select 3 out of total 14 = 14C3= 364
a) number of ways to select 3 when all are female = 5C3 = 10
probability that all are females P(A) = 10/364
probability that at least one is male P'(A)= 1 - 10/364
= 354/364
= 0.9725
b) number of ways to select 3 when all there are male = 9C3 = 84
probability that all are male P(B) = 84/364
probability that at most 2 are male P'(B)= 1 - 84/364
= 280/364
= 0.76923 (approx)
May be some calculation mistakes, try to solve it yourself.
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